hdrmerge: exposure question

gadolf · June 19, 2018, 2:43pm

So hdrmerge does something like this if I correctly understood:

1 - Finds the darkest image
2 - Sets the darkest image as 0 EV
3 - For each remaining images, EV = difference between current image EV - darkest EV

Am I correct?

Morgan_Hardwood · June 19, 2018, 3:21pm

Yes, the EV in the tooltip is relative to the darkest image.

github.com

jcelaya/hdrmerge/blob/master/src/MainWindow.cpp#L308

    
      
          }
          if (numImages > 1) {
              double logLeastExp = std::log2(images.getImage(numImages - 1).getRelativeExposure());
              for (unsigned int i = 1; i < numImages; i++) {
                  QAction * action = new QAction(QIcon(getColorIcon(i)), QString::number(i), layerSelectorGroup);
                  action->setCheckable(true);
                  double logExp = logLeastExp - std::log2(images.getImage(i - 1).getRelativeExposure());
                  action->setToolTip(QString("%1: +%2 EV").arg(QFileInfo(images.getImage(i - 1).getFilename()).baseName()).arg(logExp, 0, 'f', 2));
                  if (i < 10)
                      action->setShortcut(Qt::Key_0 + i);
                  else if (i == 10)
                      action->setShortcut(Qt::Key_0);
                  layerSelector->addAction(action);
              }
              QAction * firstAction = layerSelectorGroup->actions().first();
              firstAction->setChecked(true);
              preview->selectLayer(0);
          }
          if (numImages > 0) {
              QWidget * lastLayer = new QWidget();
              lastLayer->setContentsMargins(0, 1, 0, 0);